4NaOH + 4HCI - NaCl + H20

NaOH + HCl —> NaCl + H₂O

Explanation:

From the question given above, we obtained the following equation:

4NaOH + 4HCl —> NaCl + H₂O

The equation can be balance as follow:

4NaOH + 4HCl —> NaCl + H₂O

There are 4 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 4 in front of NaCl as shown below:

4NaOH + 4HCl —> 4NaCl + H₂O

There are a total of 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of H₂O as shown below:

4NaOH + 4HCl —> 4NaCl + 4H₂O

Next, divide through by 4 to express the equation with the lowest coefficients.

NaOH + HCl —> NaCl + H₂O

Now the equation is balanced.

NOTE: Smallest coefficients are always used to represent a balanced equation.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.