What volume of a 6.0% W/V glucose (C6H6O6) solution can be prepared using 185g of glucose?

Volume of solution : = 3083.3 ml = 3.0833 L

Given

a 6.0% w/v

185 g of glucose

Required

Volume of solution

Solution

% w/v : the mass of solute in a volume of solution or 1 g solute in 100 ml of solution

Can be formulated :

% w/v = (mass solute(g) : volume solution(ml)) x 100

Mass of solute = mass of glucose = 185 g

The volume of solution :

= 185 g : 0.06

= 3083.3 ml

= 3.0833 L

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

the answer would be a