A student obtained a test tube with a suspension of white, slightly soluble calcium hydroxide in water. This system was at equilibrium as represented by the following equation:. Ca(OH)2(s)Ca2(aq)+ 20H(aq)
Write the equilibrium constant expression for this reaction.

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]

Explanation:

Equation for the reaction is given below:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

Equilibrium constant =?

Equilibrium constant (K) for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, we can write the equilibrium constant (K) for the above reaction as follow:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

sure im new too!

explanation: