Calculate the volume in mL of 1.043 M acetic acid (CH3COOH) that is needed to prepare 50.0 mL of 0.10 M acetic acid. Show your work and give your answer to the correct number of significant figures.

4.8 mL of 1.043 M acetic acid that is needed to prepare 50.0 mL of 0.10 M acetic acid

Explanation:

According to the dilution law,

where,

= molarity of stock solution = 1.043 M

= volume of  stock solution = ?

= molarity of diluted solution = 0.10 M

= volume of diluted solution = 50.0 ml

Putting in the values we get:

Therefore, volume  in mL of 1.043 M acetic acid (CH3COOH) that is needed to prepare 50.0 mL of 0.10 M acetic acid is 4.8

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

pv=nrt

explanation: