An aqueous solution containing 9.96 g of lead(II) nitrate is added to an aqueous solution containing 5.15 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states.

Pb(NO3)2(aq) + 2KCl(aq) = PbCl2(s) + 2KNO3(aq)

Explanation:

The reaction is between;

Lead(II)nitrate - Pb(NO3)2    

potassium chloride = KCl

This is given as;

Pb(NO3)2(aq) + 2KCl(aq) = PbCl2(s) + 2KNO3(aq)

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