PLEASE HELP!! Sulfur dioxide gas and oxygen gas react to produce gaseous sulfur trioxide. What mass of sulfur trioxide is produced when 125 g of sulfur dioxide reacts with 50.00 g of oxygen to produce sulfur trioxide as the only product.
2SO2(g) + O2(g) —> 2SO3(g)

Mass = 156.195 g

Explanation:

Given data:

Mass of SO₂ = 125 g

Mass of O₂ = 50.00 g

Mass of SO₃ produced = ?

Solution:

2SO₂ + O₂   →     2SO₃

Number of moles of SO₂:

Number of moles = mass/molar mass

Number of moles = 125 g/ 64.1 g/mol

Number of moles = 1.95 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 50.00 g/ 32 g/mol

Number of moles = 1.56 mol

Now we will compare the moles of SO₃ with SO₂ and O₂

                         O₂         ;          SO₃

                          1           ;            2

                         1.56      :          2/1×1.56 = 3.12 mol

                      SO₂        ;          SO₃

                          2          ;            2

                         1.95       :          1.95

Less number of moles of SO₃ are produced by SO₂ it will act as limiting reactant:

Mass of SO₃ :

Mass = number of moles × molar mass

Mass =  1.95 mol × 80.1 g/mol

Mass = 156.195 g

it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d

16

explanation:

the marks go by 4s