Some students measure the acceleration of a wheeled cart being acted on by varying forces. The students record their data in the table shown above. According to the data table, how much force is acting on the cart when the students measure an acceleration of 2.6 m/s2? A. 13 N

B. 7 N

C. 8 N

D. 12 N

F = 13 N

Given

Acceleration= a = 2.6 m/s²

Required

Force

Solution

Newton's second law :

ΣF = m x a

The wheeled cart used in the experiment is the same, so the mass used is the same

We use one of the data for example data 1 to find mass :

F = 1 N, a = 0.2 m/s²

m = F/a

m = 1/0.2

m = 5 kg

so for acceleration= a = 2.6 m/s² :

F = 5 kg x 2.6 m/s²

F = 13 N

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

i'm pretty sure it is letter c.) car