A gas occupies 50.0mL at a standard temp. What volume would it occupy at 335 Celsius with the pressure unchanged?

V₂ = 111.3 mL

Explanation:

Given data:

Initial volume of gas = 50.0 mL

Initial temperature = standard = 273.15 K

Final volume = ?

Final temperature = 335 °C (335+273.15 = 608.15 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 50.0  mL ×608.15 K / 273.15 k

V₂ = 30407.5 mL.K / 273.15 K

V₂ = 111.3 mL