Chemistry, 19.01.2021 14:00 fmas6855

Calculate the empirical formula of lithium carbonate, if a sample contains 2.8g of lithium, 2.4g of carbon and 9.6g of oxygen.

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Answer from: markyyy53

Li₂CO₃

Explanation:

Given parameters:

Mass of lithium = 2.8g

Mass of carbon = 2.4g

Mass of oxygen = 9.6g

Unknown:

Empirical formula of the compound = ?

Solution:

The empirical formula is the simplest formula of a compound.

Elements Lithium Carbon Oxygen

Mass 2.8 2.4 9.6

Molar mass 7 12 16

Number of

moles 2.8/7 2.4/12 9.6/16

0.4 0.2 0.6

Divide by the

smallest 0.4/0.2 0.2/0.2 0.6/0.2

2 1 3

The empirical formula is Li₂CO₃

Answer from: Quest

The answer is yes b ffgnbsfgnbnfgbnfgsnb

Answer from: Quest

Ithe undersigned only for use your own email and delete any and copies and of the itself and to be there is a good timewhat does a decrease in temperature indicate about the molecules in a sample of liquid water? decreased chemical energy of the moleculesdecreased kinetic energy of the moleculesincreased chemical energy of the moleculesincreased kinetic energy of the moleculeshow does a sample of helium at 15 â°c compare to a sample of helium at 215 k? the helium at 15 â°c has a higher average kinetic energy than the sample at 215 k.the helium at 15 â°c has lower nuclear energy than the sample at 215 k.the helium at 15 â°c has slower-moving atoms than the sample at 215 k.the helium at 15 â°c has smaller atoms than the sample at 215 k.

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Calculate the empirical formula of lithium carbonate, if a sample contains 2.8g of lithium, 2.4g of...

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