Gas stored in a tank at 273 k has a pressure of 388 kpa. the safe limit for the pressure is 825 kpa. at what temperature will the gas reach this pressure? answer choices > > > > > > > > > > > . a1173k b.580k c.710k d128k hurry and and

580K

Explanation:

Initial pressure P1= 388×10^3pa

Final pressure P2= 825×10^3 pa

Initial temperature T1= 273K

Final temperature T2=

From

P1/T1 = P2/T2

T2= P2 T1/P1

T2= 825×10^3 × 273/388×10^3

T2= 580K

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

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