1. A compound is made up of 11 percent oxygen and 89 percent gold. What would be this compound's empirical formula?

Empirical formula is Au₂O₃

Explanation:

Given data:

Percentage of oxygen = 11%

Percentage of gold = 89%

Empirical formula = ?

Solution:

Solution:

Number of gram atoms of O = 11 / 16 = 0.69

Number of gram atoms of Au = 89 / 197 = 0.45

Atomic ratio:

                Au               :          O    

           0.45/0.45        :      0.69  /0.45

                    1               :           1.5      

Au  : O = 1 : 1.5

Au  : O = 2( 1 : 1.5)

Empirical formula is Au₂O₃.

um i think it might be a car?