How would you do this

The empirical formula = the molecular formula = C₁₀H₂₀O

Given

m =  0.15 g menthol

V = 0.0337 L

T = 150 +273 = 423 K

P = 100.2 kPa =0.99 atm

Required

molar mass

The molecular formula

Solution

Ideal gas law :

PV=nRT

n=PV/RT

n=0.99 x 0.0337/0.082 x 423

n=9.6 x 10⁻⁴

n =  mass/Molar mass

Molar mass = mass/n

Molar mass = 0.15/9.6 x 10⁻⁴

Molar mass = 156.25 g/mol

The empirical formula of Menthol : C₁₀H₂₀O

(The empirical formula)n= molecular formula

(C₁₀H₂₀O)n=156.25

(12.011.10+1,007.20+15,999)n=156.25

(156.25)n=156.25

n=1

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