What number of cations is present in 1.17g of sodium chloride ?

1.2 × 10^22 atoms.

Explanation:

Firstly, cations refers to the positively charged atom in the ionic compound, which is Na+.

Given the mass of NaCl as 1.17g, the number of moles of NaCl can be calculated this:

Molar mass of NaCl = 23 + 35.5

= 58.5g/mol

Mole = mass/molar mass

Mole = 1.17/58.5

Mole = 0.02moles

Using Avagadro's number, 6.022 × 10^23 atoms of Na+ are in 1 mole of NaCl.

In 0.02 moles of NaCl, there are 0.02 × 6.022 × 10^23 of Na+

0.1204 × 10^23 atoms

1.2 × 10^22 atoms of Na+ (cation)

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).