Find the volume, in Liters, of 2.5 x 1024 molecules of chlorine gas at STP.

V = 93.0 L

Explanation:

Hello!

In this case, when computing the PVT properties for an ideal gas, we need to use the following equation:

In such a way, for 2.5 x 10²⁴ molecules of chlorine at STP (273.15 K and 1.00 atm) we first need the moles based on the Avogadro's number:

Now, we solve for volume on the ideal gas equation to obtain:

So we plug in and get:

Best regards!

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole