What is the mass of sulfur (VI) oxide SO3 1.2 ⋅ 1023 molecules?

15.92g

Explanation:

Firstly, we calculate the number of moles in the molecule by saying:

Number of molecule of SO3 ÷ 6.02 × 10^23

1.2 × 10^23 ÷ 6.02 × 10^23

0.199 × 10^(23-23)

0.199 × 10^0

0.199 moles

Since there are 0.199 moles of SO3, the mass can be calculated by using;

Mole = mass ÷ molar mass

Molar Mass of SO3 = 32 + 16(3)

= 32 + 48

= 80g/mol

Mass (g) = molar mass (g/mol) × Mole (mol)

Mass = 80 × 0.199

Mass = 15.92g

the ratio of the conjugate base to the acid required to attain the desired ph.