Electric field creates a 3.9 ma current in a 1.0-mm-diameter wire. what material is the wire made of?

The wire made of Nichrome  

The ρ resistivity of an object is the ratio of the magnitude of the electric field to the current density

Can be formulated:

Current density (J) itself is the ratio of currents per unit area of cross-section

Can be formulated:

Complete questions from the assignments above can be stated as follows:

A 0.0075 V / m electric field creates a 3.9 mA current in a 1.0 mm diameter wire. What is the wire made of?

a) Aluminum (resistivity: 2.82 * 10 ^ -8)

b) Nichrome (resistivity: 1.1 * 10 ^ -6)

c) Copper (resistivity: 1.68 * 10 ^ -8)

d) Iron (resistivity: 1.0 * 10 ^ -7)

If we see the question above then to find the resistivity of the material we must find the wire cross-section area first

Known value

E = 0.0075 V / m

I = 3.9 mA = 3.9.10⁻³ A

d = 1.0 mm = 1.10⁻³ m

A = 1 / 4 π.d²

A = 1 / 4. π. (10⁻³)²

A = 1/4 . π . 10⁻⁶

so that

ρ = 1.5.10⁻⁶ ohm . m

From this value the material which approaches its resistivity is Nichrome with resistivity: 1.1 . 10⁻⁶ ohm.m

the flow of electric current.

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Electric current

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The direction of the magnetic field

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An electric current produces a magnetic field.

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the direction of the electric field

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Keywords: the magnetic field, electric current, resistivity , Nichrome  

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole