a solution is 5.00% potassium chloride by mass. how much potassium chloride would you expect to collect by evaporating 150.0 g of the solution

When 150.0g of the solution are evaporated, 7.50g of KCl must be collected

Explanation:

A solution 5% of potassium chloride means that there are 5g of KCl per 100g of solution.

When all the solution is evaporated, the solute KCl will be collected as a solid.

In 150g of solution there are:

150g * (5.00gKCl / 100g solution) = 7.50g of KCl are present in 150g of solution.

That means:

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.