0.38 L of HNO3 is titrated to equivalence using 0.14 L of 0.2 MNaOH. What is the concentration of the HNO3HNO3

0.074M is concentration of the HNO₃ solution

Explanation:

The reaction of neutralization of nitric acid, HNO₃ with NaOH is:

HNO₃ + NaOH → H₂O + NaNO₃

Where 1 mole of nitric acid reacts per mole of NaOH

Based on the chemical reaction, the moles of NaOH at equivalence point are equal to moles of HNO₃ presents in the solution. With the moles and the volume we can find molarity as follows:

Moles NaOH = Moles HNO₃:

0.14L * (0.2mol NaOH / L) = 0.028mol NaOH  = 0.028mol HNO₃

Molarity:

0.028mol HNO₃ / 0.38L =

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

14 days is the half-life of phosphorus-32