A chemist adds of a M sodium nitrate solution to a reaction flask. Calculate the millimoles of sodium nitrate the chemist has added to

The given question is incomplete. The complete question is:

A chemist adds 35.0 mL of a 2.82M sodium nitrate (NaNO3) solution to a reaction flask. Calculate the millimoles of sodium nitrate the chemist has added to the reaction flask.

98.7 mmol

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = milli moles of solute

= volume of solution in ml

Now put all the given values in the formula of molarity, we get

Therefore, the millimoles of sodium nitrate the chemist has added to reaction flask are 98.7

c

explanation: