When the absolute value of the difference in electronegativity of two adjacent atom in a compound is 1, they are most likely bonded by .

polar covalent bond

Explanation:

Compounds are formed ether by donating, receiving or sharing of electrons making the bonds between them to  be ionic, or covalent .

Now  according to the rule  of type of bond assignment due to electronegativity difference of atoms

---When the  electronegativity difference is less than 0.5,  the bond formed is nonpolar covalent.

---When   the  electronegativity difference is between 0.5 and 1.6, the bond is considered polar covalent

---When  the  electronegativity difference greater than 2.0, then the bond is ionic.

Therefore, When the absolute value of the difference in electronegativity of two adjacent atom in a compound is 1, they are most likely bonded by  polar covalent bond eg HCl bond , CCL4 bond

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.