Using the values you calculated for each of the trials, calculate an average value of Kf. Report your result to 3 significant figures. You will use this average value in the calculations for part III. (Just a reminder, while temperatures are expressed as oC on the Celsius scale, when a difference between two temperatures is taken, the result is expressed in Kelvins because the unit size of differences on the Celsius scale are identical to those on the Kelvin scale.)

if you mean hydrogen and oxygen then water is the product

pie chart because it is in percents ( % )

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o