The rate constant for the second-order reaction !s 0.54 M-1 s-1 at 300°C. How long (in seconds) would 1t take for the concentration of N02 to decrease from 0.62 M to 0.28 M?

3.63s take for the concentration of NO₂ to decrease from 0.62M to 0.28M

Explanation:

The general equation for a second-order reaction is:

1/[A] = kt + 1/[A]₀

Where [A] is actual concentration of the reactant (0.28M)

k is rate constant (0.54M⁻¹s⁻¹)

t is time the reaction takes (Our incognite)

And [A]₀ is initial concentration of reactant (0.62M)

Replacing:

1/0.28M = 0.54M⁻¹s⁻¹t + 1/0.62M

3.5714 = 0.54t + 1.6129

1.9585 = 0.54t

3.63s = t

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.