Explain why each molecule has a higher vapor pressure at a given temperature than the other in the pair. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer 1. The main reason why CHOH has a higher vapor pressure at a given temperature when compared to CH3 CH2 CH2 OH is that CH3OH
2. The main reasons why CH4 has a higher vapor pressure at a given temperature when compared to CH3 Cl is that CH4and
3. The main reasons why H2CO has a higher vapor pressure at a given temperature when compared to CH3 OH is that H2 COand
does not exhibit dispersion forces
does not exhibit dipole-dipole forces
does not exhibit hydrogen bonding
is polar
has a smaller molar mass

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

B? i feel like this is a trick