Select the correct electron configuration for Vanadium. (Atomic Number 23) 1s 22s 22p 63s 23p 84s 23d 1
1s 22s 62p 33s 23p 44s 23d 5
1s 22s 22p 63s 23p 64s 23d 3
1s 22s 22p 53s 23p 74s 13d 4

Explanation:

Vanadium is in Period 4 and in the d-block of elements. The highest energy subshell is 4s. (because as electrons fill the 3d subshell, the subshell becomes of lower energy than 4s)

We have 1s²2s²2p⁶3s²3p⁶3d³4s².

Vanadium (V) --- d-block element

Location on the periodic table :

Atomic number=23

Atomic mass=51 g/mol

The correct electron configuration for Vanadium is:

V= [Ar]4s²3d³ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³

3. 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³ is the right answer.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml