7.5 moles of nitrogen gas (N2) is formed in the following reaction. How many grams of Ammonia (NH3) are formed?
3H2 + N2 + 2NH

Mass = 255 g

Explanation:

Given data:

Number of moles of nitrogen = 7.5 mol

Mass of ammonia formed = ?

Solution:

Chemical equation:

3H₂ + N₂      →    2NH₃

Now we will compare the moles of nitrogen and ammonia.

             N₂         :        NH₃

               1          :         2

              7.5       :       2/1×7.5 = 15

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 15 mol × 17 g/mol

Mass = 255 g

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2