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The answer is 10.8 g of lH2.

Explanation:

As per the equation, let us calculate the mole ratio.

N2+3H2→2NH3

As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.

In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.

We can set up the ratio:

28.01 g of lN2 needs 6.048 g of lH2

1 g of lN2 needs 6.048 / 28.01 g of lH2

50.0 g of lN2 needs 6.048×50.0 28.01 lg of lH2

=

10.8 g of lH2

Hope this helps!! ;)

i think that the answer is c