Limestone CaCo3 decomposes to lime according to the equation below CaCo3 > CaO + CO2
(i) balance the equation above
(ii) what mass of limestone would produce 11.2 grams of lime?
Show your working

Mass of lime produced = 19.0 g

Explanation:

Given data:

Mass of lime produced = 11.2 g

Mass of limestone react = ?  

Solution:

Chemical equation:

CaCO₃     →      CaO + CO₂

Balanced chemical equation:

CaCO₃     →      CaO + CO₂

Number of moles of lime:

Number of moles = mass / molar mass

Molar mass of lime 56.1 g/mol

Number of moles = 11.2 g/ 56.1 g/mol

Number of moles = 0.19 mol

Now we will compare the moles of CaO and CaCO₃  from balance chemical equation.

                    CaO        :           CaCO₃

                      1             :             1

                     0.19          :          0.19

Mass of limestone react:

Mass = number of moles × molar mass

Mass = 0.19 mol × 100.1 g/mol

Mass = 19.0 g

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