What is the molarity of a sodium carbonate solution containing 32.52 g Na2CO3 dissolved in enough water to make 822 ml of solution? NEED ASAP PLEASE!!

The molarity of a Sodium carbonate solution : 0.373 M

Given

32.52 g Na₂CO₃

822 ml of solution = 0.822 L

Required

The molarity

Solution

Molarity shows the number of moles of solute in every 1 liter of solution.

mol of solute = mol of Na₂CO₃ :

= mass : MW Na₂CO₃

= 32.52 g : 106 g/mol

= 0.307

Molarity :

= n : V

= 0.307 mol : 0.822 L

= 0.373 M

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

6.4 cm (max) - 25 cm (min)