200mL of 12.0M HNO3 is prepared from stock solution of 16.0M HNO3. A, What volume of stock solution of NH3 is used? And b, What volume of water should be added to the stock

a. 150mL of the stock solution was added

b. 50mL of water was added

Explanation:

The solution was diluted from 16.0M to 12.0M, that is:

16.0M / 12.0M = 1.333 times was diluted.

As the volume of the diluted solution is 200mL, the amount of the 16.0M stock solution is:

200mL / 1.333 =

As the volume of the solution is 200mL and 150mL were added of the stock solution, the volume of water is:

200mL - 150mL =

the atomic mass is the bottom number on the element.

-steel jelly

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.