Imagine you have an object with a non-geometric shape having a mass of 26.7 g and a density of 0.767 g/mL. If it were placed in a graduated cylinder containing 20.0 mL
of water what would you expect the new water level to read? [Assume the sample is
completely submerged and everything is done at 25°C]

The new reading of the water level is 54.81 mL.

Explanation:

From the question given above, the following data were obtained:

Mass of object = 26.7 g

Density of object = 0.767 g/mL

Volume of water = 20 mL

New reading of the water level =?

Next, we shall determine the volume of the object. This can be obtained as follow:

Mass of object = 26.7 g

Density of object = 0.767 g/mL

Volume of object =?

Density = mass /volume

0.767 = 26.7 / volume of object

Cross multiply

0.767 × Volume of object = 26.7

Divide both side by 0.767

Volume of object = 26.7 / 0.767

Volume of object = 34.81 mL

Finally, we shall determine the new reading of the water level. This can be obtained as follow:

Volume of water = 20 mL

Volume of object = 34.81 mL

New reading of the water level =?

New reading of the water level = (Volume of water) + (Volume of object)

New reading = 20 + 34.81

New reading of the water level = 54.81 mL

3 1/4 %

explanation:

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