4) 568 cm3 of chlorine at 25° C will occupy 400 cm3 at what temperature given a constant pressure?

The final temperature : T₂=209.86 K = -63.1 °C

Given

V₁=568 cm³

T₁=25° C+ 273 = 298 K

V₂=400 cm³

Required

Final temperature(T2)

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

T₂=(V₂.T₁)/V₁

T₂=(400.298)/568

T₂=209.86 K = -63.1 °C

d.) circle motion requires a force to give it a centripetal acceleration.