Balance the equations (5pts each) and answer the posed question (5pts each) 1. C6H14 + O2 --> CO2 + H2O

When 60.00 grams of hexane is used, how many grams of water can be formed?

2 C6H14 (g) + 19 O2 (g) --> 12 CO2 (g) + 14 H2O (g)

Explanation:

For solving the stoichiometric calculations, we first need to do two steps. One of them is balancing the reaction equation. Here the balancing is done and we can see that 2 moles of hexane reacts with 19 moles of oxygen to produce 12 moles of carbon dioxide and 14 moles of water.

Now, for 2 moles of hexane, number of moles of oxygen required is 19.

So, for 7.2 moles of hexane, number of moles of oxygen required is.

= 68.4.

So 68.4 moles of oxygen is required.