Calculate the mass of a molecule of sulfur (IV) oxide
and express it in grams,
kilograms and daltons. Please help

10.63 × 10^(-24) g

10.62 × 10^(-27) kg

64 daltons

Explanation:

Formula for sulfur (IV) oxide is; SO2

Now,

Atomic mass of Sulphur is 32 while atomic mass of oxygen is 16.

Thus;atomic mass of SO2 is;

32 + (16 × 2) = 64 amu

Now,

1 mole of a substance has 6.02 × 10^(24) molecules

Therefore mass of 1 molecule of SO2 will yield;

Mass(g) = 64/(6.02 × 10^(24)) = 10.63 × 10^(-24) g

Converting to kg, we have;

10.63 × 10^(-24) ÷ 1000 = 10.62 × 10^(-27) kg

Now, converting to Dalton, we know that;

1kg = 6.022 × 10^(26) amu

Thus; 10.62 × 10^(-27) kg will yield;

(10.62 × 10^(-27) × 6.022 × 10^(26))/1 ≈ 64 amu

Now, from conversion;

1 amu = 1 Dalton.

Thus, 64 amu = 64 daltons

altitude, density, pressure

air gets less dense the higher the altitude and also the air pressure is less as altitude rises.

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