Now that you know the molar mass of the empirical formula, you can divide it into the molar
mass of your compound to find the scaling factor.
What is the scaling factor if the molar mass of
this compound, having an empirical formula of
CH20, is 150 g/mor?

The molecular formula C₅H₁₀O₅ and The scaling factor =5

Given

Molar mass = 150 g/mol

The empirical formula = CH₂O

Required

The scaling factor

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula

n = the scaling factor

(CH₂O)ₙ=150 g/mol

(12+2+16)ₙ=150

(30)ₙ=150

n=5

The molecular formula : C₅H₁₀O₅

the answer to your question is c