b
. 0.351 L.
Explanation:
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In this case, since diluted solutions are prepared by adding an extra amount of diluent to a stock-concentrated solution, we infer that the number of moles of solute remains the same, therefore we can write:
Thus, solving for the volume of the stock solution, V1, we obtain:
Now, by plugging in the given data we obtain:
Therefore, the answer is b
. 0.351 L.
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