Pls answer this asap

1. The enthalpy change for the backward reaction is –20 KJmol¯¹

2. The forward reaction is endothermic.

3. The activation energy for the forward reaction is +70 KJmol¯¹.

Explanation:

Considering the diagram given above, the following data were obtained:

1. The enthalpy change for the forward reaction being is +20 KJmol¯¹ and so, the enthalpy change for the backward reaction is –20 KJmol¯¹

2. The heat energy of the product is higher than that of the reactant. Therefore, the forward reaction is endothermic.

3. Activation energy is the minimum energy needed to be overcome in order for the reaction to proceed to product. It can be obtained from the energy profile diagram by considering the energy between the reactants and the peak.

For the question given above, Activation energy = 20 + 50

Activation energy = +70 KJmol¯¹

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :