50POINTS! Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k

If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?

A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles

A. 1.02 moles .

Explanation:

Hello!

In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:

Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:

Therefore, the correct answer is A. 1.02 moles

Best regards!

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied