6. (10 Points) The volume of a helium balloon in Los Angeles is 14.0 L The temperature in Los Angeles is 25°C. Find the volume of the balloon in
Death Values where the temperature is 52°C, with the pressure being the
same in both places.
PLS HURRY

V₂ = 15.27 L

Explanation:

Given data:

Initial volume = 14.0 L

Initial temperature = 25°C (25 + 273.15 = 298.15 k)

Final temperature = 52°C = (52+273.15 = 325.15 k)

Final volume = ?

Solution:

Charles Law:

" The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure "

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 14.0 L × 325.15 K / 298.15 k

V₂ = 4552.1 L.K / 298.15 K

V₂ = 15.27 L

the volume increases

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .