For the reaction CH4 + 2O2 = 2H2O + CO2 How many moles of water are produced from the combustion of 45.2 grams od methane (CH4)? Please show all work.

(2H2O)=5.6mol

Explanation:

45.2g produce x mole of CH4

we are given the mass of methane

mass (CH4)=45.2g

molar mass (CH4) = 12+4 =16g/mol

Mole=mass

molar mass

mole=45.2

16

mole=2.8mol

therefore, if 45.2g produce 2.8mol as 1 mole of methane, the water produced is 2(2.8) we Are multiplying by 2 because the water is having 2 moles water mole is 5.6mol

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