What volume of gold would be equal in mass to a piece of copper with a volume of 121 mL? The density of gold is 19.3 g/mL; the density of copper is 8.96 g/mL.

We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.

Explanation:

Details:

Density of Copper= 8.96 g/ml

Volume of Copper=141 ml

mass of Gold = mass of Copper

Density of Gold=19.3 g/ml

In order to solve for the mass of copper, we need to use the density formula

Density= mass/volume

Since we are to solve for the mass of copper

mass of copper= Density of Copper * Volume of Copper

mass of copper= 8.96 g/ml* 141 ml= 1263.36 g

Thus,

mass of gold=mass of copper=1263.36 g

Hence,

Using still the density formula to solve for the volume of gold,

Volume of gold=mass of gold/ Density of gold

Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL

Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.