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a. K₃PO₄ + 3 HCl ⇒ 3 KCl + H₃PO₄

b. C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O

c. KClO₃ ⇒ KCl + 1.5 O₂

Explanation:

a. Let's consider the following unbalanced equation. This is a double displacement reaction.

K₃PO₄ + HCl ⇒ KCl + H₃PO₄

We will begin balancing K atoms by multiplying KCl by 3.

K₃PO₄ + HCl ⇒ 3 KCl + H₃PO₄

Then, to balance Cl atoms, we multiply HCl by 3. This will be the balanced equation.

K₃PO₄ + 3 HCl ⇒ 3 KCl + H₃PO₄

b. Let's consider the following unbalanced equation. This is a combustion reaction.

C₂H₆ + O₂ ⇒ CO₂ + H₂O

First, we will balance C atoms by multiplying CO₂ by 2.

C₂H₆ + O₂ ⇒ 2 CO₂ + H₂O

Then, we balance H atoms by multiplying H₂O by 3.

C₂H₆ + O₂ ⇒ 2 CO₂ + 3 H₂O

Finally, we get the balanced equation multiplying O₂ by 3.5.

C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O

c. Let's consider the following unbalanced equation. This is a decomposition reaction.

KClO₃ ⇒ KCl + O₂

Since K and Cl atoms are balanced, we will get the balanced equation multiplying O₂ by 1.5.

KClO₃ ⇒ KCl + 1.5 O₂

5.6⋅10−^19  j

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