CH4 + 202 → CO2 + 2H2O
How many moles of O2 needed to react with 32 grams of CH4?

4.0 mol O₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   32 g CH₄

Step 2: Identify Conversions

[RxN] 1 mol CH₄ → 2 mol O₂

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

Step 3: Stoichiometry

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

3.98754 mol O₂ ≈ 4.0 mol O₂

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