1.What is the theoretical
 yield of C6H5Br in this reaction when 30.0 g of C6H6
reacts with excess Br2? If the 
actual yield of C6H5Br was 56.7 
g, 
what 
is
 the 
percent 
yield?

The theoretical yield of bromobenzene is 60.3 grams and the percent yield of the reaction is 94.0%.

Explanation:

Given:

Mass of benzene = 30.0 g

The actual yield of bromobenzene = 56.7 g

To find:

Theoretical yield and percent yield of the reaction.

Solution:

Mass of benzene = 30.0 g

Moles of benzene =

According to reaction, 1 mole of benzene gives 1 mole of bromobenzene, then 0.384 moles of benzene will give:

Mass of 0.384 moles bromobenzene:

The theoretical yield of bromobenzene = 60.3 g

The actual yield of bromobenzene = 56.7 g

The percent yield of the reaction:

The theoretical yield of bromobenzene is 60.3 grams and the percent yield of the reaction is 94.0%.

Learn more about the percent yield of reaction here:

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The theoretical yield in grams is 60.292 grams, and in moles the theoretical yield is 0.384. The percent yield is 94%.

Explanation:

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.