7) A gas takes up a volume of 15 liters, has a pressure of 1500 mmHg, and a temperature of 299 K. If I raise the temperature to 350 K and lower the pressure to 1050 mmHg, what is the new volume of the gas?

V₂ = 25.065 L

Explanation:

Given data:

Initial volume = 15L

Initial pressure = 1500 mmHg (1500/760 = 1.97 atm)

Initial temperature = 299 K

Final temperature = 350 K

Final volume = ?

Final pressure = 1050 mmHg (1050/760 = 1.38 atm)

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.97 atm × 15 L × 350 K / 299 K × 1.38 atm

V₂ = 10342.5 atm .L. K / 412.62 K.atm

V₂ = 25.065 L

the answer is barium and copper bromide