What mass of oxygen gas (O 2 ) required to react completely with 2 moles of C 6 H 14 ?

608g

Explanation:

This is a combustion reaction between oxygen gas and C₆H₁₄.

 The reaction expression is given as:

      2C₆H₁₄   +       19O₂   →     12CO₂    +     14H₂O

We have been given 2 moles of C₆H₁₄

  Let us find the number of moles of oxygen gas;

                     2 moles of C₆H₁₄ will react with 19 moles of O₂

Mass of oxygen gas reacting  = number of moles x molar mass

     molar mass of oxygen gas  = 2(16)  = 32g/mol

Mass of oxygen gas  = 19 x 32  = 608g

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every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.