A tire contains 1.50 mol of air at a gauge pressure of 205 kPa. If the volume of the air in the tire is 0.0120 m3, what is its temperature

197.07 K

Explanation:

To solve this problem we can use the PV=nRT equation, where:

We input the data:

And solve for T:

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3