a A student decreases the temperature of a 484 cm ^ 3 balloon from 570 K to 285 Assuming constant pressure, what should the new volume of the balloon be? Round your answer to one decimal place.

242 cm³.

Explanation:

The following data were obtained from the question:

Initial volume (V₁) = 484 cm³

Initial temperature (T₁) = 570 K

Final temperature (T₂) = 285 K

Pressure = constant

Final volume (V₂) =?

The new volume (i.e final volume) of the balloon can be obtained by using the Charles' law equation as illustrated below:

V₁/T₁ = V₂/T₂

484 / 570 = V₂ / 285

Cross

484 × 285 = 570 × V₂

137940 = 570 × V₂

Divide both side by 570

V₂ = 137940 / 570

V₂ = 242 cm³

Therefore, the new volume of the balloon is 242 cm³

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.