A certain amount of gas at 25°C and at a pressure of 0.800 atm is contained in a glass vessel. Suppose that the vessel can withstand a pressure of 2.00 atm. What is the maximum temperature in Kelvin that the gas can have without bursting the vessel? a. 745 K
b. 62.5 K
c. 298 K
d. 760 K

The maximum temperature : a. 745 K

Given

Gas at 25°C(298 K) and at a pressure of 0.800 atm

Final pressure = 2 atm

Required

Final temperature

Solution

Gay Lussac's Law  

When the volume is not changed, the gas pressure in the vessel is proportional to its absolute temperature  

Input the value :

T₂=(P₂T₁)/P₁

T₂=(2 atm x 298 K)/0.8 atm

T₂ = 745 K = 472 °C

it is b that is the answer.