4. Calculate the average atomic mass of lithium, which occurs as two isotopes that have the following atomic masses and abundances in nature: 6.017 u, 7.30%
and 7.018 u, 92.70%.

The average atomic mass is 6.94 amu.

The Atomic mass of the first isotope = 6.017 amu

Atomic mas off second isotope = 7.018 amu

The abundance of first isotope = 7.30%

The abundance of second isotope = 92.70%

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

= (7.30×6.017)+(92.70×7.018) /100

=  43.924 + 650.57 / 100

= 694.494 / 100

= 6.94 amu.

Learn more about the mass here: link

Average atomic mass = 6.94 amu.

Explanation:

Given data:

Average atomic mass = ?

Atomic mass of first isotope = 6.017 amu

Atomic mas off second isotope = 7.018 amu

Abundance of fist isotope = 7.30%

Abundance of second isotope = 92.70%

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (7.30×6.017)+(92.70×7.018) /100

Average atomic mass =  43.924 + 650.57 / 100

Average atomic mass  = 694.494 / 100

Average atomic mass = 6.94 amu.

i'm assuming that it's c.) red bank..

the temperature of the gas, in k, not celsius.