The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles of air.
Next, cancel like terms and units. Which of the following shows the correct terms and units canceled?

The answer is B, edge 2021

The mass of air : 96.5 g air

Given

The molecular mass of air, at STP : 28.97 g/mol.

3.33 moles of air

Required

The mass

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

mol = mass : molar mass

mass = mol x molar mass

Input the value :

mass = 3.33 moles air x 28.97 g air/1 mol air

mass = 96.47 g ≈ 96.5 g air

answer: option (4) is the correct answer.

explanation:

areas which are at low altitudes and near the equator tend to receive direct sunlight from the sun. hence, heat energy or radiations from the sun make these areas warmer and they have warmest water.

whereas areas which are at high altitudes and away from the equator do no receive direct sunlight. hence, no direct contact from the sun makes these regions colder and thus, they have colder water.

thus, we can conclude that the statement areas at low latitudes near the equator have the warmest water because they receive the most direct sunlight best explains the relationship between an area's geography and the temperature of its surface water.

the answer is na (sodium)